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Hi Jessie, Let me try a3 b1 times a2 b5. You can write this as
What I have now is five a's and six b's and I can write this as
Hence
Notice that what I did was collect the three a's from a3 with the two a's from a2 to get five a's. In other words
Similarly
so all I need to do is add the exponents. Let's try another,
I hope this helps, | ||||||||||||
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