



 
Hi Jessie, Let me try a^{3} b^{1} times a^{2} b^{5}. You can write this as
What I have now is five a's and six b's and I can write this as
Hence
Notice that what I did was collect the three a's from a^{3} with the two a's from a^{2} to get five a's. In other words
Similarly
so all I need to do is add the exponents. Let's try another,
I hope this helps,  


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