



 
Hi John, Let me illustrate by dividing 3c^{2} + 4c  9 by 3c  8. First I divide 3c into 3c^{2} and get c so start the quotient with c and multiply 3c  8 by c. Subtract 3c^{2}  8c from 3c^{2} + 4c to get 12c. Bring down 9 to get At this stage divide 3c into 12c to obtain 4 so the next term in the quotient is 4. Multiply 3c  8 by 4. Finally subtract 32 from 9 to obtain a remainder of 23. Thus 3c^{2} + 4c  9 by 3c  8 is c + 4 with a remainder of 23. Now try your problem,  


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