Hi John,

Let me illustrate by dividing 3c² + 4c - 9 by 3c - 8.

First I divide 3c into 3c² and get c so start the quotient with c and multiply 3c - 8 by c.

Subtract 3c² - 8c from 3c² + 4c to get 12c. Bring down -9 to get

At this stage divide 3c into 12c to obtain 4 so the next term in the quotient is 4. Multiply 3c - 8 by 4.

Finally subtract -32 from -9 to obtain a remainder of 23.

Thus 3c² + 4c - 9 by 3c - 8 is c + 4 with a remainder of 23.

Now try your problem,
Harley