SEARCH HOME
Math CentralQuandaries & Queries

Question from JOHN:

IF YOU HAD A RATE OF 678/HOUR AND YOUR NEW RATE/HOUR
IS NOW 1961 WHAT IS PERCENT OF IMPROVEMENT

John,

Percent change is the change as a percentage of the starting value. The change in your case is
1961 - 678 = 1283 dollars/hour. 1283 as a percentage of 678 is 1283/678 × 100 = 186.75%.

Penny

About Math Central
* Registered trade mark of Imperial Oil Limited. Used under license.
 

 


Math Central is supported by the University of Regina and the Imperial Oil Foundation.
Quandaries & Queries page Home page University of Regina Imperial Oil Foundation