



 
We have two responses for you Joshua, Have you tried letting the integers be n, n+1,n+2 & n+3? Then your statement implies 2(n+2+n+3) = 3n+91? Penny
Hi Joshua. They are consecutive integers, so call the lowest one L. Then the "Twice the sum of the two greater integers..." "...exceeds three times the first by 91." So Can you solve for L now? Cheers,
 


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