 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Question from Kim, a parent: I have a 6 digits. My hundred-thousands digit is 1 less that my ones digit, 8 more than my thousands digit, twice my tens digit, and 4 times my hundreds digit. My ten-thousands digit is 0. What number am I? |
Hi Kim.
Let's say the digits are (in order): abc,def.
"My hundred-thousands digit is 1 less that my ones digit"
So a = f - 1. So a must be from 0 to 8 and f must be from 1 to 9.
"[my hundred-thousands digit is] 8 more than my thousands digit"
So a = c + 8. So a must be 8 or 9, but since we already know it cannot be 9, then a = 8.
If a = 8, then c = 0. and f = 9.
Complete the problem this way using this as your head start.
Cheers,
Stephen La Rocque.
| ||
| ||
| ||
 |
 |
|
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.