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Question from Kristian, a student:

f(x)= the square of x add to 1 and g(x)=1/x

find: (f o g)x

Kristian,

I am going to solve a similar problem.

f(x) = (x + 2)2 and g(x) = 1/x - 3

find (f o g)x

The expression (f o g)x is another way of writing f(g(x)). Let's evaluate this first with x a particular number, say x = 5. To evaluate f(g(5)) you first evaluate

g(5) = 1/5 - 3 = - 2 4/5.

Hence

f(g(5)) = f(- 2 4/5) = (- 2 4/5 + 2)2 = (-4/5)2 = 16/25

Now do it again using the variable x.

g(x) = 1/x - 3

Hence

f(g(x)) = f(1/x - 3) = (1/x - 3 + 2)2 = (1/x - 1)2

Now try your problem. If you need further assistance write back.

Penny

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