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| Math Central | Quandaries & Queries |
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Question from Krystal, a student: May rides her bike the same distance that leah walks. May rides her bike 10km/h faster than leah walks. |
Hi Krystal,
The key here is in the units. The rate at which each travels is in km/h which is distance/time so
rate = distance/time or distance = time × rate
Suppose Leah rides at L km/h then since she rides for 3 hours her distance is
distance = 3 × L.
What is May's rate? She sides for 1 hour so what is her distance?
The two distances are the same so this gives you an equation that you can solve for L>
I hope this helps,
Penny
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