



 
Manashi, Try working backwards, Manashi. A quadratic with rational roots is factored as (ax + b)(cx + d) = px^{2} + qx + r. Thus, ac = p, bd = r and (ad+bc) = q. You know that p=ac is odd, so both a and c are odd. What can you conclude from ac = p, bd = r and (ad+bc) = q? Cheers,
 


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