



 
Hello Meghan, The substitution for this integral requires a little trick to eliminate all of the x’s. You have the integral so doing your substitution you let u = x^{3} + 1 and then du = 3x^{2} dx and simplifying this you get 1/3 du = x^{2} dx. However in our integral we have an x^{5} not an x^{2}, but we can split up the x’s in the integral a bit to make it easier for us. So we take our integral and split up the x’s Then from here you can integrate with respect to u, and then substitute u = x^{3} + 1 back in after you have integrated to reach your final solution. I hope this helps. Happy integration. Brennan Yaremko  


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