



 
Hi Nicole, This problem is asking you to consider all possible rectangles with the same area. You are not told what the area is so the algebraic technique is to give the area a name, say A, and think of this name (letter) as a number. Each of these rectangles has a certain length and width and we know that the area of a rectangle is the length times the width. Thus if the length is L and the width is W then
You are also told that among all these rectangles the one with the smallest perimeter is a square. For a square L = W and hence if you can find the length L then you also know the width. For the square
The question then come to
I hope this helps,  


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