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| Math Central | Quandaries & Queries |
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Question from Nisha, a student: In triangle ABC, LM is parallel to AB. If AL=x-3,AC=2x,BM=x-2,BC=2x=3. Find x |
Hi Nisha,
I think you have a diagram that looks like
Since LM is parallel to AB the triangles ABC and LMC are similar. Hence, in particular
|CA|/|BC| = |CL|/|MC|
Thus
2x/(2x - 3) = |CL|/|MC|
Hoe long is CL? How long is MC? substitute these values and solve for x.
Penny
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