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Question from Nisha, a student:

In triangle ABC, LM is parallel to AB. If AL=x-3,AC=2x,BM=x-2,BC=2x=3. Find x

Hi Nisha,

I think you have a diagram that looks like

triangle

Since LM is parallel to AB the triangles ABC and LMC are similar. Hence, in particular

|CA|/|BC| = |CL|/|MC|

Thus

2x/(2x - 3) = |CL|/|MC|

Hoe long is CL? How long is MC? substitute these values and solve for x.

Penny

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