



 
Nomaan, I think the easiest way to factor this is to remove the factor of x^{2} from the first two terms
and then take out a common factor of (x  2) from the two resulting terms. To use the factor theorem let f(x) = x^{3}  2 x^{2}  x + 2 and then notice that f(1) = 0. Thus by the factor theorem (x  1) is a factor of f(x). Divide f(x) by (x  1) to obtain g(x) so that f(x) = (x  1) g(x). Factor g(x). Penny  


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