



 
Hi Rachel, Finding the domain of this function is straightforward. The denominator factors x^{2}  3x  4 = (x  4)(x + 1) so x = 4 and x = 1 "break" the function. No other values of x cause a problem so the domain is all real numbers x except x = 4 and x = 1. Determining the range is more of a challenge. As Chris says in the answer to an earlier question
I used a computer program to draw a graph. f(x) = (3x^{3}  2x^{2} +6x  7)/(x^{2} 3x 4) From the graph I can see that the range of the function is all real numbers. I hope this helps,  


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