



 
Hi Randy. Here's how I would do it as fast as I can: Step 1: put the equation of the circle in (mostly) standard form. to do this, I complete the square, ignoring the radius
Step 2: find the slope of the tangent line. this is the negative reciprocal of the radius from the circle's center to the
Step 3: plug the slope and point of tangency into the pointslope form of linear equation:
Finished. Is that quick enough? Cheers,  


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