



 
Hi Rita, Let me try a couple of other points. Are (0,1) and (4,60) on the graph of y = x^{3}  2√x? First consider (0, 1). When x = 0 the right side of the equation is 0^{3}  2√0 = 0 and the left side is y = 1. The left side is not equal to the right side so (0, 1) is not on the graph. For (4, 60) the right side is 4^{3}  2√4 = 64  4 = 60 and the right side is y = 60. The left side is equal to the right side so (4, 60) is on the graph. I hope this helps,  


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