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Question from Robert, a student:

A rectangle is three times as long as it is wide. If the length is decreased by 2 cm and the width is increased by 3 cm, the new rectangle has an area of 42 cm. What are the dimensions of the original rectangle?

I am having trouble setting this problem up correctly.

Rob

Hi Rob,

Suppose that the rectangle has length L cm and width W cm. Look at the first two sentences in the question.

A rectangle is three times as long as it is wide.

This says that L = 3W

If the length is decreased by 2 cm and the width is increased by 3 cm, the new rectangle has an area of 42 cm.

Decreasing the length by 2 cm makes the new rectangle L - 2 cm long. Increasing its width by 3 cm makes it W + 3 cm wide. This new rectangle has an area of 42 square cm and hence length × width = 42 or

(L - 2)(W + 3) = 42

From the first equation you know that L = 3W and thus you can substitute 3W for L in the second equation and solve for W.

I hope this helps,
Penny

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