



 
Rougi, Part a) can be reworded "The first student goes to one of the bars. What is the probability the second and third student choose the same bar?" Seen this way the probability that the second student chooses the same bar is 1/4 and the probability that the third student also choose this bar is 1/4. Since these are independent events the probability they both choose the bar the first student chose ia 1/4 × 1/4 = 1/16. Penny Rougi wrote back. hi again best regards Rougi, You can use the same technique I used in part a). The first student goes to one of the bars. What is the probability that the second student chooses a different bar? Once the first and second students are in bars what is the probability that the third student chooses a different bar? Penny  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 