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Hi again Rougi, Each ticket holder either shows up or doesn't. I am going to say that "success" is the event that the ticket holder doesn't show up. The probability of success p is then 0.04. Let X be the number of successes, that is the number of people who don't show up. If everyone who shows up gets a seat then X must be 5 or more. Thus you want
Use the binomial distribution to find the probability that X is 0 or 1 or 2 or 3 or 4. Harley | ||||||||||||
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