I checked out the integration site, but would like an explanation for integrating this integral

Tan^3[x] * _dx__
Cos^2[x]

Hope this input is correct!
the part that throws me off is Tan^3[x], if it was squared rather than cubed I would have a easier time
dealing with this one.

Hi Russell,

If I am reading thi2 correctly you need to integrate tan^{3}(x) divided by cos^{2}(x). Write 1/cos^{2}(x) as sec^{2}(x) and then the integrand is tan^{3}(x) sec^{2}(x) . Try the substitution u = tan(x).

Harley

Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.