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 Question from Russell, a student: I checked out the integration site, but would like an explanation for integrating this integral Tan^3[x] * _dx__ Cos^2[x] Hope this input is correct! the part that throws me off is Tan^3[x], if it was squared rather than cubed I would have a easier time dealing with this one.

Hi Russell,

If I am reading thi2 correctly you need to integrate tan3(x) divided by cos2(x). Write 1/cos2(x) as sec2(x) and then the integrand is tan3(x) sec2(x) . Try the substitution u = tan(x).

Harley

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