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Question from Russell, a student:

I checked out the integration site, but would like an explanation for integrating this integral

Tan^3[x] * _dx__
Cos^2[x]

Hope this input is correct!
the part that throws me off is Tan^3[x], if it was squared rather than cubed I would have a easier time
dealing with this one.

Hi Russell,

If I am reading thi2 correctly you need to integrate tan³(x) divided by cos²(x). Write 1/cos²(x) as sec²(x) and then the integrand is tan³(x) sec²(x) . Try the substitution u = tan(x).

Harley

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