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However I expect you are to use algebra. So how do you express two consecutive odd positive integers algebraically? An odd number is one more than an even number so if n is any nonnegative integer 2n + 1 is odd. The next number is 2n + 2 which is eve and the next number is 2n + 3 which is odd. Thus 2n + 1 and 2n + 3 are two consecutive odd positive integers. Hence you need to find n if
Expand this expression to obtain a quadratic in n. Factor the quadratic and solve for n. You already know that 2n + 1 = 5 and 2n + 3 = 7 so that's a check on your work. Penny  


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