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Question from stev, a student:

as x->0. How do you find the limit of f(x)=(sin4x)/(tan9X)

Thank you

Hi Stev,

First write tan(9x) as sin(9x)/cos(9x) and f(x) can then be written

sin(4x)/tan(9x)

As x approaches 0, cos(9x) approaches 1. Thus all that remains is to find the limit of sin(4x)/six(9x) as x approaches zero. For this I suggest you look at the responses Stepehen and I gave to Josh for his problem.

Harley

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