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| Math Central | Quandaries & Queries |
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Question from SWAPNA, a student: Evaluate the following limit using L'Hospitals Rule |
Swapna,
let y = [(sin x)/x]1/x2 and considet ln(y).
ln(y) = 1/x2 ln((sin x)/x)
Since the limit of (sin x)/x is 1 as x approaches zero and ln(1) = 0 ln(x) meets the requirements for applying l'Hospital's rule.
Harley
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