



 
Hi Sylvia, I am going to solve a similar problem.
You don't know either the numerator or denominator of the fraction so let the numerator be n and the denominator be d. The first sentence says
Translating that into the language of algebra it is
Hence the fraction can be written
Now look at the second sentence. Double the denominator [2(3n + 1)] and add 2 to the numerator [n + 2] and form the resulting fraction [(n + 2)/(6n + 2)]. You are told that the value of this fraction is 1/4 which means that the fraction (n + 2)/(6n + 2) is equivalent to the fraction 1/4. Hence if you know the value of n and form (n + 2)/(6n + 2) there will be some cancellation of factor in the numerator and denominator to obtain the result 1/4. In other words
Thus n + 2 = k and 6n + 2 = 4k. Substituting the first equation into the second gives
or
and thus
Hence the original fraction is 3/10. Check:
Now try your problem,  


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