



 
Hi Tiffany, If I asked you to find the quadratic equation with roots 3 and 2 could you find it? I think you could. Since the quadratic has roots 3 and 2 it would factor as (x  3)(x + 2) and expanding this gives x^{2} x 6. The question you sent us asks to find the quadratic with roots 3  i and its complex conjugate 3 + i. Using the same technique this quadratic is (x  [3  i])(x  [3 + i]) = (x  3 + i)(x  3  i). Expand this expression. When you have the quadratic in standard form you can use the general quadratic or complete the square to find the roots which should be 3  i and 3 + i. Penny  


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