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| Math Central | Quandaries & Queries |
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Question from Tom, a student: I am having trouble with this question. For y > 1, the value of cosec [arccos (1/y)] is? So far i have let arccos (1/y) = theta so , cos theta = 1/y The answer is y/ sqroot (y*2 - 1), what are the steps in getting this answer, and is there a general rule for working these out? Thankyou. |
Hi Tom,
I would draw a diagram. If arccos (1/y) = theta then
Use Pythagoras theorem to find the length of the third side of the triangle. From the diagram what is cosec(θ)?
Penny
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