



 
In March 2012 Mike, a high school teacher in New York, pointed out an error on this page. Hi Tom, The quick answer is it depends on the stadium and the conditions. Using some basic Physics equations, we can figure out how high and far the ball can travel under ideal conditions. You would need to know the horizontal distance from home plate to the edge of the opening of the stadium and also height from the field. Here are the assumptions I am making:
Since the path of the ball is at an angle, we need to break down the initial velocity into horizontal velocity and vertical velocity.
We know that acceleration due to gravity is 9.81m/s/s (it will slow down the vertical velocity). The vertical velocity as the hits the ground will be the same velocity but opposite sign of the initial vertical velocity. We can use these facts to determine the total time the ball will travel (if uninterrupted). Since the path is assumed to be parabolic, the maximum height (the vertex) is half the time of the total time. Time $v_f = v_i + at$ $v_f  v_i = at$ $\large \frac{ v_f  v_i }{a} = t$ $\large \frac{ 34.77 m/s34.77 m/s }{9.81 m/s^2} =\normalsize t$ $t = 7.09 s$ From the initial velocities, time when the height is at the maximum and acceleration due to gravity, we can determine the maximum height of the path (the vertex). At the vertex $t = \large \frac{7.09}{2} \normalsize = 3.54 \; s.$
Now that we know the vertex, we can find the equation of the parabolic path. From the equation of the parabola, we can find the height of the ball at 320 ft (the distance to the right back wall).
Hope this answers your question,  


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