|
|||||||||||||||||||||
|
|||||||||||||||||||||
| |||||||||||||||||||||
|
Well, calculators aside, you can do some quick arithmetic as follows by using multiples of 23 like 230, 2300, etc. 2300-230 =2070 is clearly a multiple of 23 so what would the remainder be if we divided (2070-2050)*(2070-2071)*(2070-2095) = 20*(-1)*(-25) by 23 and how would this relate to your question? (You could simplify even further by looking at (-3)*(-1)*(-2) instead of 20*(-1)*(-25); why?). I think your answer should be 17. What is really going on here is the idea behind modular arithmetic, hope this helps, Penny |
|||||||||||||||||||||
|
|||||||||||||||||||||
| Math Central is supported by the University of Regina and the Imperial Oil Foundation. | |||||||||||||||||||||