CB,

I'm going to illustrate with a similar problem.
Solve ln(1/3 x²) + 2 ln(3) = ln(15 x)
I need to use two of the properties of logs which are

a ln(b) = ln(b^a) and ln(a * b) = ln(a) + ln(b)

Thus 2 ln(3) = ln(3²) = ln(9) and hence

ln(1/3 x²) + 2 ln(3) = ln(1/3 x²) + ln(9) = ln(1/3 * 9 x²) = ln(3 x²)

Hence ln(1/3 x²) + 2 ln(3) = ln(15 x) becomes

ln(3 x²) = ln(15 x) or 3x² = 15x

Therefore

3x² - 15x = 0
3x(x-5) = 0

Hence x = 0 or x = 5.

But ln(0) is undefined so the only solution is x = 5.

I hope this helps,
Penny