



 
Hi Lisa. The question is much harder if the bearings are not fully submerged in the oil, so we have to either assume that or prove it. If the volume of the ball bearings is considerably smaller than the volume of oil, then they'll be submerged. The volume of oil is the volume of the cylinder up to the top of the liquid. So this is a cylinder that is 4 cm deep. A cylinder's volume is π r^{2} d, where d is the depth and r is the radius. So the volume of oil is (3.1416)(8^{2})(4) = 804.24 ml. The volume of a ball bearing is the volume of a sphere. The formula for the volume of a sphere is (4/3) π r^{3}, so 100 ball bearings with radius 0.5 cm (it helps to make sure all measurements are in the same units) is (100)(4/3)(3.1416)(0.5^{3}) = 52.36 ml. So the volume of the ball bearings is much smaller than the volume of oil and they'll be submerged. So to answer the question, you need to ask yourself whether the ball bearings float. If they float on top of the oil, then the level of oil doesn't rise at all. If they sink, then they will displace as much oil as the space they take up: in other words, the level of the oil has to rise to compensate for the 52.36 ml of ball bearings. Thus, you need to find the depth d for 52.36 ml of volume V in the cylinder using the formula
where you know V is 52.36 ml and r is 8 cm. Solve for d. Cheers,
 


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 