



 
Alisha, csc(θ) = 1/sin(θ) and sec(θ) = 1/cos(θ) and hence you have sin(θ) = 1/3 and cos(θ) = 1/√3. Thus
But for any angle θ, sin^{2}(θ) + cos^{2}(θ) = 1. Hence there is no angle θ such that csc(θ) = 3 and sec(θ) = √3. A better question would be
Harley  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 