



 
Hi Ayana, On the left side there is a common factor in the numerator and the denominator can be factored as a difference of squares. Perform these factorizations and then cancel what you can. Solve the resulting equation for x. Now you need to check that the result you obtained is actually a solution to the equation. First of all x can't be 2 or 2. If your solution is 2 or 2 then the original equation has no solution. If your solution is not 2 or 2 substitute it into the original equation to verify that it is a valid solution to the original equation. I hope this helps,  


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