



 
Don, I found this on the web page http://www.maa.org/editorial/mathgames/mathgames_08_14_07.html: "28 golfers can play in foursomes for 9 days. If quadruples are picked so that every pair occurs once, S(2, 4, 28), a Steiner 2design is the solution, and there are 4466 such solutions. From these, there are 7 different resolvable designs, two of them coming from the Ree unital. One of these solutions gives a schedule for our golfers. Day1 ABCD EFGH IJKL MNab cdef ghij klmn You could use it twice, changing which golfer corresponds to which letter the second time in order to get different foursomes. And do that again but use only the first six days. This is about as good as one can do. Everyone plays together 46 times. Have fun!  


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