Duane,

Try this. Break the golfers into four groups of six. Say:

The first collection of foursomes is the columns: 1, 7, 13, 19; 2, 8, 10 , 14; etc.
The second set of foursomes is 1, 8, 15, 22; 2, 9, 16, 23; 3, 10, 17, 24; 4, 11, 18, 19; 5, 12, 13, 20; 6, 7, 14, 21
The third set is 1, 9, 17, 19; 2, 10, 18, 20; 3, 11, 13, 21; 4, 12, 14, 22,; 5, 7, 14, 23; 6, 8, 16, 24
The fourth set is 1, 10, 13, 22; 2, 11, 14, 23; 3, 12, 15, 24; 4, 7, 16, 19; 5, 8, 17, 20; 6, 9, 18, 14
The fifth set is 1, 11, 15, 19; 2, 12, 16, 20; 3, 7, 17, 21; 4, 8, 18, 22; 5, 9, 13, 23; 6 10, 14, 24
The sixth set is 1, 12, 17, 22; 2, 7, 18, 23; 3, 8, 13, 24; 4, 9, 14, 19; 5, 10, 15, 20; 6, 11, 16, 21

This takes case of all pairs belonging to different groups of six. Now for the rest. I think this works:
Day 7: 1, 2, 3, 4; 5, 6, 7, 8; 9, 10, 11, 12; 13, 14, 15, 16; 17, 18, 19, 20; 21, 22, 23, 24
Day 8: 3, 4, 5, 6; 7, 8, 9, 10; 11, 12, 13, 14; 15, 16, 17, 18; 19, 20, 21, 22; 23, 24, 1, 2
Day 9: 5, 6, 1, 2; 7, 8, 11, 12; 13, 14, 17, 18; 19, 20, 23, 24; 3, 4, 9, 10; 15, 16, 21, 22

In the last three days some pairs (ex. 1 and 2) are together every day. There are 12 such pairs. There might be a better way to do it. Can you see one? Otherwise, keep friendships in mind when numbering the players.

Have fun.
Victoria