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| Math Central | Quandaries & Queries |
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Question from Emily, a student: a vending machine contains nickels and dime coins which totals an amount of $14.50. There are 95 more nickels than the number of dime coins. How many of each coin does exist? |
Hi Emily,
Suppose the number of nickles is n and the number of dimes is d then the value of the nickles is 5n cents and the valure of the dimes is 10d cents. The total in the machine is 1450 cents and hence
5n + 10d = 1450.
There are more nickles than dimes, in fact 95 more so
n = 95 + d.
Substitute this value of n into the first equation and solve for d.
Penny
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