Math CentralQuandaries & Queries


Question from Emily, a student:

a vending machine contains nickels and dime coins which totals an amount of $14.50. There are 95 more nickels than the number of dime coins. How many of each coin does exist?
The # of Dimes____ The # of nickels.
PS: please help

Hi Emily,

Suppose the number of nickles is n and the number of dimes is d then the value of the nickles is 5n cents and the valure of the dimes is 10d cents. The total in the machine is 1450 cents and hence

5n + 10d = 1450.

There are more nickles than dimes, in fact 95 more so

n = 95 + d.

Substitute this value of n into the first equation and solve for d.


About Math Central


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.
Quandaries & Queries page Home page University of Regina PIMS