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Question from Jaquanta, a student:

A local water park has 2 types of season passes. Plan A costs a one - time fee of $142 for admission plus $8 for parking every trip. Plan B costs a one - time fee of $56 for parking plus $25 for admission every trip. How many visits must a person make for plan A and plan B to be equal in value?

Jaquanta,

You could just do some arithmetic.

Number of visits Cost
Plan A
Cost
Plan B
1 $142 + 1 × $8 = $150 $56 + 1 × $25 = $81
2 $142 + 2 × $8 = $158 $56 + 2 × $25 = $106
3

But this is too much work!

Let's try some algebra.

What is the cost for plan A if the number of visits is x?
What is the cost for plan B if the number of visits is x?

Make the two expressions above equal and solve for x.

If you need additional help write back.

Penny

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