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| Math Central | Quandaries & Queries |
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Question from Jaquanta, a student: A local water park has 2 types of season passes. Plan A costs a one - time fee of $142 for admission plus $8 for parking every trip. Plan B costs a one - time fee of $56 for parking plus $25 for admission every trip. How many visits must a person make for plan A and plan B to be equal in value? |
Jaquanta,
You could just do some arithmetic.
| Number of visits | Cost Plan A |
Cost Plan B |
|---|---|---|
| 1 | $142 + 1 × $8 = $150 | $56 + 1 × $25 = $81 |
| 2 | $142 + 2 × $8 = $158 | $56 + 2 × $25 = $106 |
| 3 | … | … |
But this is too much work!
Let's try some algebra.
What is the cost for plan A if the number of visits is x?
What is the cost for plan B if the number of visits is x?
Make the two expressions above equal and solve for x.
If you need additional help write back.
Penny
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