



 
Hi Jim, (x  4)^{3/2} can be written [(x  4)^{3}]^{1/2} so in particular if x = 8 then (x  4)^{3/2} can be evaluated as
What I want you to notice is that the last operation I performed was a square root and the square root is never negative. Thus (x  4)^{3/2} can't possibly be 6 so your equation has no solution. Penny  


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