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Jim, What you want is easily seen to be impossible: any one person plays with three others in a foursome, so that FIVE foursomes would be required for that person to play with all 15 other golfers. Happily, a symmetric arrangement can be organized for five rounds. We have a description of that arrangement in our archives: For your golf trip, you just use the first four rounds from the table. In fact, for whichever of the four rounds you use, each golfer will play one time with each of 12 others. Chris
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |