|
||||||||||||
|
||||||||||||
| ||||||||||||
Juan, Look at my note to another student on completing the square and use it to write y = x2 - 6x + 13 in the form y = (x-a)2 + b. Solve this equation for x by writing (x-a)2 = y - b and taking the square root of both sides. This gives two solutions
and
To decide which is the inverse of F(x) draw a sketch of y = x2 - 6x + 13. You may find it helpful to use the form y = (x-a)2 + b when constructing the graph. I hope this helps, | ||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |