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Question from Kelly, a parent:

find a quadratic equation with roots (4-i) and (4+i)

Hi Kelly,

The quadratic expression x2 - 2x + 15 can be factored to give x2 - 2x - 15 = (x - 5)(x + 3). Thus the quadratic equation x2 - 2x + 15 = 0 has roots x = 5 and x = -3. You can perform this from the end to the beginning.

One quadratic equation with roots 5 and -3 is (x - 5)(x + 3) = 0. Expanding this gives x2 - 2x + 15 = 0.

What I am saying is a quadratic equation with roots a and b is (x - a)(x - b) = 0. This fact is true, even if a and b are complex numbers. Hence one quadratic equation with roots 4 - i and 4 + i is

[x - (4 - i)][x - (4 + i)] = 0.

Expand the left side.

When you are finished you can use the quadratic formula to verify that 4 - i and 4 + 1i are roots.

Harley

 

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