



 
Kristen, Since 5, 1 + 2i and 1  2i are all zeros, (x  5), (x  1  2i) and (x  1 + 2i) are all factors. Thus the polynomial must be of the form
Expand the right side. [I would find (x  1  2i)(x  1 + 2i) first and then multiply by (x  5).] What is the value of k is f(2) = 1? Harley  


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