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| Math Central | Quandaries & Queries |
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Question from marylyne, a student: the perimeter of the rectangular is 70 meters. if the width is 40% of the length, find the dimensions? |
Marylyne,
Suppose the length is L meters and the width is W meters.
The perimeter is then L + W + L + W = 2L + 2W meters.
Since W is 40% of L, W = 0.40 × L.
Hence you have three facts.
- The perimeter is 70 meters.
- The perimeter is 2L + 2W meters.
- W = 0.40 × L.
Put these three facts together to form an equation in the variable L. Solve this equation for L.
Penny
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