



 
Hi Michele, All the signs in the expression 6x^{2}+19x+3 are positive and hence if you can factor it you will have
for some integers a, b, c and d. Since the only factorization of 3 is 3 × 1, b and d are 1 and 3 or 3 and 1 so you are looking for a and c so that
6 can be factored as 6 = 3 × 2 or 6 = 6 × 1 so the only possibilities for a and c are
For each possibility expand (ax + 1)(cx + 3) and see if any of them yield 6x^{2}+19x+3. Penny  


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