



 
Hi Mukulu. Log_{7} is how I write "log in base 7". And Log_{14} is how I write "log in base 14". So you have Log_{7} (4x) = Log_{14} (x). Step 1: Let y = Log_{14}(x). This gives us: Step 2: Raise both sides under the base of 7: Step 3: Since y = Log_{14}(x), let's raise this equation under base 14: Step 4: Substitute x from Step 3 into Step 2 equations: Can you finish the problem now? x works out to a nice simple number. Cheers,  


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