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| Math Central | Quandaries & Queries |
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Question from Nazrul, a teacher: How can I solve sinA-cosA=1 where 0 degree<=A<=90 degree. Thank you. |
Nazrul,
One way to approach this problem is to use sin2A = 1 - cos2A and hence write
√(1 - cos2A) = 1 + cosA.
Square both sides and solve the resulting equation for cosA. Select the solutions for which 0 ≤ A ≤ 90o and verify that any solutions actually satisfy the original equation.
Harley
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