



 
Hi Raymond, If anyone can sit anywhere you could just ask,
I'm going to illustrate with 3 people to save me some typing.
I have three people Mary, Bob and Susan and three chairs in a row. I am going to start by placing someone i the first chair. I have three choices so after seating the first person the arrangement is one of the three possibilities
Regardless of who I seat first I now have two choices for the second seat. The possibilities are
Hence at this stage there are 3 × 2 = 6 possible seating arrangements. For each of these there is just one choice for the final seat so the possible arrangements are
The number of possible arrangements is then 3 × 2 × 1 = 6. Now try your problem with 8 people. Penny  


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