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Question from sela, a student:

An isosceles triangle has two equal sides of length 10 cm. Theta is the
angle between two equal sides.
a) Express area of a triangle as a function of theta
b) If theta is increasing at a rate of 10 degrees/minute, how fast is area
changing at the instant theta=pi/3?
c) at what value of theta will the triangle have the maximum area?

Sela,

I can get you started.

triangle

AM is perpendicular to BC and hence by the symmetry of this isosceles triangle |MC| = b/2 cm and the measure of angle CAM is θ/2 degrees. Thus cos(θ/2) = h/10 and sin(θ/2) = b/20. Hence the area of the triangle is

1/2 b × h = 100 sin(θ/2) cos(θ/2).

A trig identity will greatly simplify this expression. Do you know what it is?

Penny

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