



 
Sela, I can get you started. AM is perpendicular to BC and hence by the symmetry of this isosceles triangle MC = b/2 cm and the measure of angle CAM is θ/2 degrees. Thus cos(θ/2) = h/10 and sin(θ/2) = b/20. Hence the area of the triangle is
A trig identity will greatly simplify this expression. Do you know what it is? Penny  


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