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Sela, I can get you started. AM is perpendicular to BC and hence by the symmetry of this isosceles triangle |MC| = b/2 cm and the measure of angle CAM is θ/2 degrees. Thus cos(θ/2) = h/10 and sin(θ/2) = b/20. Hence the area of the triangle is
A trig identity will greatly simplify this expression. Do you know what it is? Penny | ||||||||||||
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |