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Sundar, First you need a point on the curve y = f(x) = ax3+bx2+cx+d, let's call it (p, q), then q = f(p). Next you need the slope of the tangent to the curve at (p, q). This slope is the derivative of f(x) evaluated at p, that is the slope is f '(p). The slope of the normal to the curve y = f(x) at x = p is -1/f '(p) and thus the normal to y = f(x) at x = p is the line through (p f(p)) with slope -1/f '(p). Penny | ||||||||||||
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |