Math CentralQuandaries & Queries


Question from yinna, a student:

how do I find the base of a triangle who's height is 2 times the base and the area is 9?


You know that the area A of a triangle is given by

A = 1/2 b × h

where b is the base length and h is the height. Thus for your triangle you know that

9 = 1/2 b × h

You are told that for this triangle the "height is 2 times the base", that is h = 2 × b. In the equation above substitute 2 × b for h. This gives you an equation in b alone. Solve it for b.

I hope this helps,

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