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| Math Central | Quandaries & Queries |
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Question from yinna, a student: how do I find the base of a triangle who's height is 2 times the base and the area is 9? |
Yinna,
You know that the area A of a triangle is given by
A = 1/2 b × h
where b is the base length and h is the height. Thus for your triangle you know that
9 = 1/2 b × h
You are told that for this triangle the "height is 2 times the base", that is h = 2 × b. In the equation above substitute 2 × b for h. This gives you an equation in b alone. Solve it for b.
I hope this helps,
Penny
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