



 
Hi Mukulu, If we know that X/5=(Y+2)/2= (Z1)/4 we can use substitution to find each of the values. First we need to find the value of one of the variable, x is the easiest to solve for: X/5=(Y+2)/2= (Z1)/4 X=5(Y+2)/2= 5(Z1)/4 now we can use either 5(Y+2)/2 or 5(Z1)/4 in the place of X, I will choose 5(Y+2)/2 3X+4Y+2Z25=0 3[5(Y+2)/2]+4Y+2Z25=0 15(Y+2)/2 + 4Y+2Z25=0 23Y/2 + 2Z=10 Since we know (Y+2)/2= (Z1)/4 then (Y+2)/2 (Z1)/4 =0 or Y/2 Z/4=5/4 Now using simple linear algebra, you can solve for Y & Z using 23Y/2 + 2Z=10 Y/2 Z/4=5/4 Once you know Y & Z, you can use X=5(Y+2)/2= 5(Z1)/4 to find X Hope this helps, Janice  


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