



 
Hi Alannah, Any triangle inscribed in a semicircle, will have a right angle. If either angle B or C are 90^{o} then the triangle would not be inscribed: That means that angle A is 90^{o} so BC must be the hypotenuse. We can use trig ratios to find length of the height and base of the triangle. cosB = adjacent side to B/ hypotenuse = AB/10 ⇒ AB = 10 cos B sinB = opposite side to B/ hypotenuse = AC/10 ⇒ AC = 10 sin B The formula for the area with respect to angle B Area = 0.5bh=50 cosB sinB Hope this helps, Janice  


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